Answers to Kinematics Homework
Vectors and Scalars (Page 1)
1. D (1998 PI Q1)
2. B (1997 PI Q1)
3. E (1995 PI Q1)
4. E (1992 PI Q1)
Vector Diagrams (Pages 2-5)
1. 3.85km at 021.2o
2. 125 nautical miles at 227o
3. 279.6 knots at 085.6o
4. Change
5. Change
6. S = 158.11m at 071.6o (1998 PI Q31)
7. VRes = 45.8m/s at 350.3o (1997 PII Q1c)
8. C (1996 PI Q2)
9a. Vectors: magnitude and direction. (1995 PII Q1)
Scalars: magnitude only.
b.i. S = 535.7m at 067.5o
b.ii. VAndy = 1.15m/s at 067.5o
b.iii. VPaul = 2.5m/s
b.iv. Andy ahead of paul by 48.4s
Resolution of Vectors (Pages 5-6)
1. E (1992 PI Q5)
2. B (1997 PI Q7)
3.a. FRes = 281.9N (1997 PI Q31a/b)
b. FRes = -281.9N
4. C (1999 PI Q1)
5. D (1996 PI Q4)
Velocity / Acceleration Time Graphs(Pages 7-13)
1. D (1993 PI Q1)
2. C (1994 PI Q4)
3. E (1999 PI Q3)
4. A (1992 PI Q2)
5. A (1998 PI Q2)
6. C (1995 PI Q2)
7. C (1997 PI Q2)
8. C (1996 PI Q1)
9. A (1999 PI Q2)
10. aAB = 2m/s2
aBC = 4m/s2
aCD = 1m/s2
aDE = -2m/s2
aEF = 0m/s2
aFG = -8m/s2
11. Acceleration Time Graph
12a. 3m/s2
12b. Velocity Time Graph
12c. Acceleration Time Graph
13.a. a = -1.6m/s2
b.
c.
14a. (0 to 0.5)s : Ball is in free fall. Downward acceleration of 10m/s2.
(0.5s) : Ball strikes ground.
(0.5 t0 1.0)s : Ball travels upwards with decreasing velocity.
(1.0s) : Ball reaches maximum height.
(1.0 to 1.5)s : Ball accelerates towards the earth at 10m/s2.
(1.5s) : Ball strikes ground.
(1.5 t0 2.0)s : Ball travels upwards with decreasing velocity.
(2.0s) : Ball reaches maximum height.
(2.0 to 2.5)s : Ball accelerates towards the earth at 10m/s2.
15a. P: Launch
Q: Engines cut out.
R: Maximum height reached.
S: Lands on planet surface.
15b. Acceleration time graph.
15c. -4m/s2
Acceleration and Equations of Motion: Non Projectile ( Pages 14 to 16)
1. (1999 PII Q1bi/ii)
2. (1994 PI Q31)
3. (1998 PII Q1a)
4. 100m
5. D (1998 PI Q3)
6. C (1994 PI Q3)
7. A (1997 PI Q3)
8. B (1993 PI Q2)
9.a.i S = 98m (1999 PII Q1ai/ii/iii)
a.ii. Vincrease = 11.6m/s
a.iii. S = 320m
10.a. t = 5s (1995 PII Q2a/b/c)
b. vP = 8m/s
vQ = 6m/s
c. S = 5m
Equations of Motion: Projectiles ( Pages 17 to 23)
1. D (1995 PI Q4)
2. B (1996 PI Q5)
3. B (1995 PI Q3)
4. D (1998 PI Q4)
5. B (1996 PI Q3)
6. C (1992 PI Q4)
7. C (1999 PI Q5)
8. D (1997 PI Q4)
9. D (1997 PI Q5)
10. E (1999 PI Q4)
11. vv = 25m/s
vH = 43.3m/s
12i. True
ii. False
iii.False
13a. 44.1m
b. Vreultant = 12m/s
c. Vreultant = 31.75m/s
14a. SH = 251.2m
b. Sv = 52.7m
15.a. Vver=7(m/s) (1999 PI Q31a/b)
b.
16.a. VHor = 12m/s (1993 PI Q31a/b)
b. SHor = 312m
17. (1996 PI Q31)
18.(A) t = 0.3s
(B) vhor = 3.33(m/s)
(C) vres = SQRT(v2hor + v2ver)
vres = SQRT(3.332 + 2.942)
vres = 4.44m/s
19. t = 2.86s
20.a.i. (1994 PII Q1ai)
a.ii. vH = 9.3m/s (1994 PII Q1aii)
b. (1994 PII Q1b)
Motion and Energy ( Pages 24 to 25)
21. C (1992 PI Q8)
22. D (1993 PI Q4)
23.a.i. (1992 PII Q2ai)
a.ii. s = 1120m (1992 PII Q2aii)
b.i. (1992 PII Q2bi)
b.ii. sver = 125m (1992 PII Q2bii)